document.write( "Question 97760: Solve the system:\r
\n" ); document.write( "\n" ); document.write( "2x + 4y = -8
\n" ); document.write( "3x + 2y = 0 \n" ); document.write( "

Algebra.Com's Answer #71132 by vincy_fyah(4) $\"\"$ $\"About$

You can put this solution on YOUR website!
set x as the subject of equation 2 which implies that $\"x=+-2y%2F3\"$ ,\r
\n" ); document.write( "\n" ); document.write( "so you substitute x in equation 2 $\"2%28-2y%2F3%29%2B4y-8=0\"$ this is factorised to give $\"-4y%2B12y-24=0\"$ , then $\"8y=24\"$ and $\"y=3\"$ \r
\n" ); document.write( "\n" ); document.write( "Take the value of y and substitute it for the y value in equation 1.\r
\n" ); document.write( "\n" ); document.write( " $\"2x%2B4%283%29=-8\"$ , $\"2x=-8-12\"$ , $\"2x=-20\"$ , $\"x=-20%2F2\"$ , therfore $\"x=-10\"$ , so when $\"y=3\"$ , $\"x=-10\"$ \r
\n" ); document.write( "\n" ); document.write( "Hope this helps :-) \n" ); document.write( "

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