document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=97771>Question 97771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi!! How do you solve this equation as a quadratic equation????? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71129 by </B><A HREF=/tutors/aboutme.mpl?userid=Msgenes><B>Msgenes(10)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Msgenes><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71129\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Which method are you supposed to use? Completing the square or using the quadratic formula. \r<BR>\n" );
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document.write( "I am using the completing the square method. \r<BR>\n" );
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document.write( "3x^2 = 10x\r<BR>\n" );
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document.write( "We have to get the 10x on the other side and we do that by substracting 10x on both sides\r<BR>\n" );
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document.write( "3x^2 - 10x = 10x -10x\r<BR>\n" );
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document.write( "3x^2 - 10x = 0\r<BR>\n" );
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document.write( "Now we need x^2 to be by itself and we do that by dividing by 3.\r<BR>\n" );
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document.write( "3x^2 - 10x = 0<BR>\n" );
document.write( "..............<BR>\n" );
document.write( "3       3\r<BR>\n" );
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document.write( "x^2 - 10x = 0<BR>\n" );
document.write( "     ....<BR>\n" );
document.write( "       3<BR>\n" );
document.write( "Now we are able to complete the square by taking half 0f 10x/3 in other words divid 10x/3 by 2 then we square it.\r<BR>\n" );
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document.write( "(10x/3)/2 = (5/3)^2 = 25/9\r<BR>\n" );
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document.write( "Now we add 25/9 to both sides.\r<BR>\n" );
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document.write( "x^2 - 10x + 25 = 25<BR>\n" );
document.write( "      .............<BR>\n" );
document.write( "       3    9    9\r<BR>\n" );
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document.write( "Now we have to factor this out. \r<BR>\n" );
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document.write( "(x - 5/3)^2 = 25/9\r<BR>\n" );
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document.write( "Now we take the square root on both sides. \r<BR>\n" );
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document.write( "Sqrt(x - 5/3)^2 = Sqrt 25/9\r<BR>\n" );
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document.write( "We will have two solutions. \r<BR>\n" );
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document.write( "x - 5/3 = 5/3<BR>\n" );
document.write( "So here again we need to get x by itself and we do that by adding 5/3 on both sides. <BR>\n" );
document.write( "x - 5/3 + 5/3 = 5/3 + 5/3<BR>\n" );
document.write( "x = 10/3\r<BR>\n" );
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document.write( "For the second solution we will do the opposite of the first one. \r<BR>\n" );
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document.write( "x + 5/3 = 5/3\r<BR>\n" );
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document.write( "x + 5/3 - 5/3 = 5/3 - 5/3\r<BR>\n" );
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document.write( "x = 0\r<BR>\n" );
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document.write( "Normally the problem would be written using the plus or minus sign. And that is completing the Square. I hopes this helps. Good Luck. :)<BR>\n" );
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