document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1096889>Question 1096889</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangular lawn is 1350 square feet. If the length of the lawn is 21 feet less than thrice it’s width, find the dimensions of the lawn  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711280 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711280\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w and 3w-21 be the width and the length of the lawn, respectively. Then:<BR>\n" );
document.write( "w(3w-21)=1350<BR>\n" );
document.write( "3w²-21w-1350=0<BR>\n" );
document.write( "w²-7w-450=0<BR>\n" );
document.write( "(w+ 18)(w-25)=0<BR>\n" );
document.write( "w=25 or -18<BR>\n" );
document.write( "The lawn is 25' by 54'<BR>\n" );
document.write( "&#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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