document.write( "Question 1096800: Rahim averaged 70 in his first m number of exams. After taking n more exams, he had an overall averaged of 75. In terms of m & n, his averaged for the last n exams was
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Algebra.Com's Answer #711257 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Rahim averaged 70 in his first m number of exams. \n" ); document.write( " After taking n more exams, he had an overall averaged of 75. \n" ); document.write( " In terms of m & n, his averaged for the last n exams was. \n" ); document.write( ": \n" ); document.write( "let a = the average of the n exams \n" ); document.write( " \n" ); document.write( "multiply both sides aby (m+n) \n" ); document.write( "70m + an = 75(m+n) \n" ); document.write( "70m + an = 75m + 75n \n" ); document.write( "solve for a \n" ); document.write( "an = 75m - 70m + 75n \n" ); document.write( "an = 5m + 75n \n" ); document.write( "a = \n" ); document.write( " \n" ); document.write( " |