document.write( "Question 1096800: Rahim averaged 70 in his first m number of exams. After taking n more exams, he had an overall averaged of 75. In terms of m & n, his averaged for the last n exams was
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Algebra.Com's Answer #711257 by ankor@dixie-net.com(22740)\"\" \"About 
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Rahim averaged 70 in his first m number of exams.
\n" ); document.write( " After taking n more exams, he had an overall averaged of 75.
\n" ); document.write( " In terms of m & n, his averaged for the last n exams was.
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\n" ); document.write( "let a = the average of the n exams
\n" ); document.write( "\"%28%2870m%2Ban%29%29%2F%28%28m%2Bn%29%29\" = 75
\n" ); document.write( "multiply both sides aby (m+n)
\n" ); document.write( "70m + an = 75(m+n)
\n" ); document.write( "70m + an = 75m + 75n
\n" ); document.write( "solve for a
\n" ); document.write( "an = 75m - 70m + 75n
\n" ); document.write( "an = 5m + 75n
\n" ); document.write( "a = \"%28%285m%2B75n%29%29%2Fn\" is the average for the last n exams
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