document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1096791>Question 1096791</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular air filter is 3 inches less than twice the width. Find the length and width of the filter if the area is 299 square inches  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711240 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w be the width of the air filter, and 2w-3 be its' length. Then:<BR>\n" );
document.write( "w(2w-3)=299<BR>\n" );
document.write( "2w²-3w-299=0<BR>\n" );
document.write( "(2w+23)(w-13)=0<BR>\n" );
document.write( "w=13 or -11.5<BR>\n" );
document.write( "Using the positive value, we get 13\" as the width of the filter, and 23\" as the length<BR>\n" );
document.write( "&#9786;&#9786;&#9786;&#9786;  </SPAN>\n" );
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