document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1096827>Question 1096827</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ramiro walks to work each morning. During the first minute he walks 80 metres. In each subsequent he walks 90% of the distance walked during the previous minute. <BR>\n" );
document.write( "The distance between his house and work is 660 metres. Ramiro leaves his house at 08:00 and has to be at work by 08:15. Explain why he will not be at work on time.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711234 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a geometric series with a ratio of 0.9<BR>\n" );
document.write( "The sum of 15 terms (until 8:15) is a1(1-r^n)/(1-r), where a1 is the distance walked the first minute, r=0.9 and 0.9^15=0.2059<BR>\n" );
document.write( "Sum=80(0.7941)/0.1<BR>\n" );
document.write( "= 635.28 m < 660 m. </SPAN>\n" );
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