document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1096825>Question 1096825</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three consecutive terms of a geometric sequence are x - 3, 6 and x + 2. <BR>\n" );
document.write( "Find the possible values of x.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711224 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711224\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the ratios between adjacent products should be equal<BR>\n" );
document.write( "6/(x-3)=(x+2)/6<BR>\n" );
document.write( "cross multiply<BR>\n" );
document.write( "x^2-x-6=36<BR>\n" );
document.write( "x^2-x-42=0<BR>\n" );
document.write( "(x-7)(x+6)=0<BR>\n" );
document.write( "x=-6, 7 ANSWER<BR>\n" );
document.write( "For -6, the series is -9,6,and -4, a ratio of -(2/3)<BR>\n" );
document.write( "For 7,  the series is 4,6,9 for a ratio of 2/3<BR>\n" );
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