document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1096817>Question 1096817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pilot in an ultra-light aircraft knows that her plane in landing configuration will glide a horizontal distance of 22 Km from a height of 1900 meters. A TV transmitting tower is located in a direct line with the local runway. If the pilot glides over the tower with 50 meters to spare, and touches down on the runway at a point 7 Km from the base of the tower, how high is the tower? Hint: use similar triangles (however, it is not the only way to solve this problem) (extra bonus points for using Matlab or Excel) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711218 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Drawing this helps\r<BR>\n" );
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document.write( "The big triangle is 1.9 km vertical and 22 km horizontal.<BR>\n" );
document.write( "The smaller triangle is x+0.05 km vertical and 7 km horizontal.<BR>\n" );
document.write( "1.9/22=(x+0.05)/7<BR>\n" );
document.write( "cross-multiply<BR>\n" );
document.write( "13.3=22x+1.1<BR>\n" );
document.write( "12.2=22x<BR>\n" );
document.write( "x=0.5545 km tower height or 554.5 m<BR>\n" );
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document.write( "Can do by trig<BR>\n" );
document.write( "the angle made by the glider has a tangent of 1.9/22, which is 0.0864<BR>\n" );
document.write( "the arc tan of that is an angle of 4.936 degrees.<BR>\n" );
document.write( "Use that to find the height of the tower x.  First, the side will be x+50, because the glider is traveling 50 m above the tower. The other side is 7 km<BR>\n" );
document.write( "tangent 4.936=(x+0.50)/7<BR>\n" );
document.write( "7 * 0.0864=x+0.05<BR>\n" );
document.write( "0.6048-0.05=x=0.5548 km or 554.8 m <BR>\n" );
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document.write( "7 km is a little less than 1/3 the total distance, and 554.8 m is a little less than 1/3 the total height from 22 km of 633 m.\r<BR>\n" );
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