document.write( "Question 1096819: Can someone help me to finish this problem. Thanks for help.
\n" );
document.write( "The pressure of the oil in reservoir tends to drop with time. By taking sample pressure readings for a particular oil reservoir, petroleum engineers have found that the change ..... is given by the function P(t)=t^3-18t^2+81t where t is time in years from the date of the first reading.
\n" );
document.write( "a) Find P(0), P(3), P(5), P(10)
\n" );
document.write( "Over what period is the change(drop) in pressure decreasing; 3 to 10 or 3 to 9?
\n" );
document.write( "___________________________________
\n" );
document.write( "a) P(0)=0 right?
\n" );
document.write( "b) P(3)=3^-18*3^2+81*3
\n" );
document.write( " P(3)=90
\n" );
document.write( "c) P(5)=?
\n" );
document.write( "d) P(10)=?\r
\n" );
document.write( "\n" );
document.write( "How to do the P(5) and P(10)?
\n" );
document.write( "Over what period is the change(drop) in pressure decreasing; 3 to 10 or 3 to 9? \n" );
document.write( "
Algebra.Com's Answer #711213 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! P(0) is 0. \n" ); document.write( "P(3)=3^3-18(3^2)+81(3)=27-162+243=108. This is a cubic equation, and the first term is cubed. \n" ); document.write( "P(5)=5^3-18(25)+81(5)=125-450+405=80 \n" ); document.write( "P(10)=10^3-18(100)+81(10)=1000-1800+810=10. \n" ); document.write( "Check P(9)=9^3-18(81)+81(9)=729-1458+729=0 \n" ); document.write( "The drop is from P(3) to P(9), and the graph shows that as well. \n" ); document.write( " |