document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1096821>Question 1096821</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find last&#8203; year's salary&#8203; if, after a 4 %4% pay&#8203; raise, this&#8203; year's salary is $ 34 comma 840$34,840. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #711210 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=711210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=Po(1+r)^n is general formula for interest. P is new salary, Po the beginning salary.<BR>\n" );
document.write( "34,840=Po(1+.04); the new salary after a raise of the old salary for 1 year.<BR>\n" );
document.write( "1.04Po=34840<BR>\n" );
document.write( "Po=$33500, initial salary. </SPAN>\n" );
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