document.write( "Question 1096630: You invested 25,000 in two accounts paying 3% and 4% annual interest, respectively. If the total interest earned for the year was $990, how much was invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #711053 by addingup(3677) $\"\"$ $\"About$

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at 3% = x
\n" ); document.write( "at 4% = 25,000-x
\n" ); document.write( "0.03x + 0.04(25,000-x) = 990
\n" ); document.write( "0.03x + 1,000 - 0.04x = 990
\n" ); document.write( "-0.01x = -80
\n" ); document.write( "x = 8,000 this is the amount invested at 3%
\n" ); document.write( "The amount invested at 4%:
\n" ); document.write( "25,000 - 8,000 = 17,000
\n" ); document.write( " \n" ); document.write( "

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