document.write( "Question 1096569: The perimeter of a rectangular plot of land is 70 meters. The length of a diagonal is 25 meters. calculate the length and width of the plot \n" ); document.write( "
Algebra.Com's Answer #711037 by ankor@dixie-net.com(22740)\"\" \"About 
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The perimeter of a rectangular plot of land is 70 meters.
\n" ); document.write( "2L + 2w = 70
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "L + w = 35
\n" ); document.write( "L = -w + 35, we can use this form for substitution
\n" ); document.write( ":
\n" ); document.write( " The length of a diagonal is 25 meters.
\n" ); document.write( "\"L%5E2+%2B+w%5E2+=+25%5E2\"
\n" ); document.write( "\"L%5E2+%2B+w%5E2+=+625\"
\n" ); document.write( "Replace L with (-w+35)
\n" ); document.write( "\"%28-w%2B35%29%5E2+%2B+w%5E2+=+625\"
\n" ); document.write( "FOIL (-w+35)(-w+35)
\n" ); document.write( "\"w%5E2+-+35w+-+35w+%2B+1225+%2B+w%5E2+=+625\"
\n" ); document.write( "arrange as a quadratic equation
\n" ); document.write( "\"2w%5E2+-+70w+%2B+1225+-+625+=+0\"
\n" ); document.write( "\"2w%5E2+-+70w+%2B+600+=+0\"
\n" ); document.write( "simplify divide by 2
\n" ); document.write( "\"w%5E2+-+35w+%2B+300+=+0\"
\n" ); document.write( "You can use the quadratic formula; a=1;b=-35;c=300, but this will factor to:
\n" ); document.write( "(w-15)(w-20) = 0
\n" ); document.write( "two solution
\n" ); document.write( "w = 15 m is the width, then the length 35 - 15 = 20 m
\n" ); document.write( "or
\n" ); document.write( "w = 20 m is the width, then the length is 15 m
\n" ); document.write( ":
\n" ); document.write( " calculate the length and width of the plot: 20 by 15
\n" ); document.write( ":
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check this solution by finding the diagonal
\n" ); document.write( "d = \"sqrt%2820%5E2+%2B+15%5E2%29\"
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