document.write( "Question 1096586: if the length of the rectangle is reduced by 5 units and its breadth is increased by 3 units then the area of rectangle is reduced by 8 square units. if length is reduced by 3 units and breadth is increased by 2 units, then the area of rectangle will increase by 6 7 square units. Then find the length and breadth of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #711032 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! I am going to ignore the 7 in the last sentence \n" ); document.write( ": \n" ); document.write( "Write an equation for each and reduce to a simple 2 unknown equation \n" ); document.write( ": \n" ); document.write( " if the length of the rectangle is reduced by 5 units and its breadth is increased by 3 units then the area of rectangle is reduced by 8 square units. \n" ); document.write( "(L-5)(w+3) = LW - 8 \n" ); document.write( "FOIL \n" ); document.write( "LW + 3L - 5w - 15 = LW - 8 \n" ); document.write( "LW - LW + 3L - 5W = 15 - 8 \n" ); document.write( "3L - 5w = 7 \n" ); document.write( ": \n" ); document.write( " if length is reduced by 3 units and breadth is increased by 2 units, then the area of rectangle will increase by 6 square units.] \n" ); document.write( "(L-3)(w+2) = Lw + 6 \n" ); document.write( "Lw + 2L - 3w - 6 = Lw + 6 \n" ); document.write( "Lw - Lw + 2L - 3w = 6 + 6 \n" ); document.write( "2L - 3w = 12 \n" ); document.write( ": \n" ); document.write( "Using these two equations \n" ); document.write( "3L + 5w = 7 \n" ); document.write( "2L - 3w = 12 \n" ); document.write( "multiply the 1st by 2 and the 2nd by 3 \n" ); document.write( "6L + 10w = 14 \n" ); document.write( "6L - 9w = 36 \n" ); document.write( "----------------subtraction eliminates L find w \n" ); document.write( "0 - w = - 22 \n" ); document.write( "w = 22 units is the width \n" ); document.write( ": \n" ); document.write( "Find the Length using the 1st equation \n" ); document.write( "2L - 3(22) = 12 \n" ); document.write( "2L - 66 = 12 \n" ); document.write( "2L = 12 + 66 \n" ); document.write( "2L - 78 \n" ); document.write( "L = 78/2 \n" ); document.write( "L = 39 units is length \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Find the original area: 39 * 22 = 858 sq units \n" ); document.write( ": \n" ); document.write( "see if this checks out in the statement: \n" ); document.write( "\" if the length of the rectangle is reduced by 5 units and its breadth is increased by 3 units then the area of rectangle is reduced by 8 square units. \n" ); document.write( "(39-5) * (22+3) = 858 - 8 \n" ); document.write( "34 * 25 = 850 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You can check for yourself in the 2nd statement\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |