document.write( "Question 1096549: If there are 35 coins worth $2.20,how many nickels and dimes are in the bank? \n" ); document.write( "
Algebra.Com's Answer #710995 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! Despite the sloppy wording of your question, the intention is clear.... \n" ); document.write( "For an informal solution, first imagine that all 35 coins are dimes; the amount would then be $3.50. But the actual amount is $2.20, which is $1.30 less than $3.50. \n" ); document.write( "Next imagine replacing 1 dime with 1 nickel repeatedly. Each time you do that, the total value goes down by $0.05 (5 cents). How many times do you need to do that to get the total down to the actual amount of $2.20? \n" ); document.write( "The value goes down by $0.05 each time; you need to reduce the value by $1.30. $1.30 divided by $0.05 is 26; you need to replace 26 of the dimes with nickels. \n" ); document.write( "So there are 26 nickels, which means the number of dimes is 35-26 = 9. \n" ); document.write( "CHECK: 9($0.10) + 26($0.05) = $0.90 + $1.30 = $2.20. \n" ); document.write( " |