document.write( "Question 1096502: Use the compound interest formulas A=P(1+r/n)^nt and A=Pe^rt to solve
\n" ); document.write( "Find the accumulated value of an investment of $140 at 3% compounded annually for 16 years. Show work.
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Algebra.Com's Answer #710935 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Use the compound interest formula: \r
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\n" ); document.write( "\n" ); document.write( "\"A+=+P%281%2Br%2Fn%29%5E%28n%2At%29\"\r
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\n" ); document.write( "\n" ); document.write( "where,\r
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\n" ); document.write( "\n" ); document.write( "A = amount in the account after t years
\n" ); document.write( "P = initial amount invested
\n" ); document.write( "r = interest rate (in decimal form)
\n" ); document.write( "n = compounding frequency
\n" ); document.write( "t = number of years\r
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\n" ); document.write( "\n" ); document.write( "In this case,\r
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\n" ); document.write( "\n" ); document.write( "A = unknown (we're solving for this)
\n" ); document.write( "P = 140
\n" ); document.write( "r = 0.03 (3% = 3/100 = 0.03)
\n" ); document.write( "n = 1 (the money is compounded 1 time per year)
\n" ); document.write( "t = 16\r
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\n" ); document.write( "\n" ); document.write( "Plug all these values into the formula to get...\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+P%281%2Br%2Fn%29%5E%28n%2At%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+140%281%2B0.03%2F1%29%5E%281%2A16%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+140%281%2B0.03%29%5E%281%2A16%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+140%281.03%29%5E%281%2A16%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+140%281.03%29%5E%2816%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+140%281.60470643909879%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+224.65890147383\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+224.66\" Round to the nearest cent (hundredth)\r
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\n" ); document.write( "\n" ); document.write( "Final Answer: $224.66\r
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