document.write( "Question 1096472: At the city museum, child admission is
\n" ); document.write( "$5.90
\n" ); document.write( " and adult admission is
\n" ); document.write( "$9.70
\n" ); document.write( ". On Wednesday, twice as many adult tickets as child tickets were sold, for a total sales of
\n" ); document.write( "$784.30
\n" ); document.write( ". How many child tickets were sold that day? \n" ); document.write( "

Algebra.Com's Answer #710902 by greenestamps(13200) $\"\"$ $\"About$

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Since the number of adult tickets was twice the number of child tickets, make a \"packet\" of two adult tickets and 1 child ticket. The cost of each of those packets is
\n" ); document.write( " $\"2%289.70%29%2B5.90+=+19.40%2B5.90+=+25.30\"$

\n" ); document.write( "Now divide the total ticket sales by the cost of one of these packets, to find how many packets were sold:
\n" ); document.write( " $\"784.30%2F25.30+=+31\"$

\n" ); document.write( "31 of the packets were sold; that means 62 adult tickets and 31 child tickets.

\n" ); document.write( "Answer: 31 child tickets were sold. \n" ); document.write( "

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