document.write( "Question 1096413: In a geometrical progression the sum of the 2nd and the 3rd terms is 6 and the sum of the 3rd and 4th term is -12.Find the 1st term and the common ratio. \n" ); document.write( "

Algebra.Com's Answer #710826 by KMST(5328) $\"\"$ $\"About$

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If the first term is $\"b\"$ , and the common ratio is $\"r\"$ ,
\n" ); document.write( "the second, third, and fourth terms are respectively
\n" ); document.write( " $\"br\"$ , $\"br%5E2\"$ and $\"br%5E3\"$ .
\n" ); document.write( "The problem says that
\n" ); document.write( " $\"br%2Bbr%5E2=6\"$ --> $\"br%281%2Br%29=6\"$ , and that
\n" ); document.write( " $\"br%5E2%2Bbr%5E3=-12\"$ ---> $\"br%5E2%281%2Br%29=-12\"$
\n" ); document.write( " $\"system%28br%281%2Br%29=-6%2Cbr%5E2%281%2Br%29=-12%29\"$ --> $\"br%5E2%281%2Br%29%2F%28br%281%2Br%29%29=%28-12%29%2F6\"$ --> $\"highlight%28r=-2%29\"$
\n" ); document.write( " $\"system%28r=-2%2Cbr%281%2Br%29=6%29\"$ --> $\"-2b%28-2%2B1%29=6\"$ --> $\"-2b%28-1%29=6\"$ --> $\"2b=6\"$ --> $\"b=6%2F2\"$ --> $\"highlight%28b=3%29\"$ \n" ); document.write( "

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