document.write( "Question 1096409: 4x^2-5x=0 \n" ); document.write( "
Algebra.Com's Answer #710816 by addingup(3677)\"\" \"About 
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4x^2-5x=0
\n" ); document.write( "this equation is in standard form, ax^2+bx+c = 0, though in this particular equation c = 0, like this:
\n" ); document.write( "4x^2-5x+0 = 0
\n" ); document.write( "So we solve it right away using the quadratic formula, first + and then -:
\n" ); document.write( "(-b+-sqrt(b^2-4ac)/2a
\n" ); document.write( "x = (-(-5)+sqrt(-5)^2)/2*4
\n" ); document.write( "x = (5+(sqrt25))/8
\n" ); document.write( "x = (5+5)/8
\n" ); document.write( "x = 10/8
\n" ); document.write( "x = 5/4
\n" ); document.write( "Now for -:
\n" ); document.write( "x = (-(-5)-(sqrt(-5)^2)/2*4
\n" ); document.write( "x = 5-5/8
\n" ); document.write( "x = 0/8 = 0\r
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