document.write( "Question 534794: A box contains 50 balls numbered from 1 to 50. If 10 balls are drawn with replacement, what is the probability that at least two of them have the same number? \r
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document.write( "Any help would be appreciated! Thank you! \n" );
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Algebra.Com's Answer #710815 by Alyrian(2)![]() ![]() ![]() You can put this solution on YOUR website! The previous solution was almost correct with a little flaw in counting.\r \n" ); document.write( "\n" ); document.write( "So you want the number of permutations of size 10 from 50, with replacement. \n" ); document.write( "This is just 50^10, or n^r.\r \n" ); document.write( "\n" ); document.write( "Then you need to find the number of PERMUTATIONS without replacement, as this \n" ); document.write( "will give you the numbers of ways you can rearrange 10 distinct object picked \n" ); document.write( "from 50. \n" ); document.write( "This is 50P10, nPr.\r \n" ); document.write( "\n" ); document.write( "Then the probability of drawing 10 balls and not getting any matches is \n" ); document.write( "50P10/50^10\r \n" ); document.write( "\n" ); document.write( "This is the complement of what you're actually looking for, so subtract this \n" ); document.write( "value from 1 \n" ); document.write( "1 - 50P10/50^10\r \n" ); document.write( "\n" ); document.write( "The numerical value is 0.61829331945. \n" ); document.write( " |