document.write( "Question 97695This question is from textbook intro alg blitzer
\n" ); document.write( ": Solve for h.
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\n" ); document.write( "S= 2 Pi rh + 2 Pi r(to the 2nd power)\r
\n" ); document.write( "\n" ); document.write( "Here's what I got.
\n" ); document.write( " S = h
\n" ); document.write( " ---------
\n" ); document.write( " 2 Pi r + 2 Pi r(to the 2nd power)\r
\n" ); document.write( "\n" ); document.write( "Am I missing a step or is this correct?
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Algebra.Com's Answer #71079 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for h:
\n" ); document.write( "\"S+=+2%28pi%29rh%2B2%28pi%29r%5E2\" Subtract \"2%28pi%29r%5E2\" from both sides.
\n" ); document.write( "\"S-2%28pi%29r%5E2+=+2%28pi%29rh\" Now divide both sides by \"2%28pi%29r\"
\n" ); document.write( "\"%28S-2%28pi%29r%5E2%29%2F2%28pi%29r+=+h\"
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