document.write( "Question 97667: One leg of a right triangle is 2 inches smaller than the hypotenuse. The other leg is 5 inches long. What are the lengths of the unknown leg and hypotenuse? \r
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document.write( "Not sure if I set it up right. \r
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document.write( "(x+2)^2 + 5^2 = x^2
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Algebra.Com's Answer #71076 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! LET X BE THE HYPOTENUSE. \n" ); document.write( "ONE SIDE=(X-2) \n" ); document.write( "THE OTHER SIDE=5 \n" ); document.write( "(X-2)^2+5^2=X^2 \n" ); document.write( "X^2-4X+4+25=X^2 \n" ); document.write( "-4X+29=0 \n" ); document.write( "-4X=-29 \n" ); document.write( "X=-29/-4 \n" ); document.write( "X=7.25 ANSWER FOR THE LENGTH OF THE HYPOTENUSE. \n" ); document.write( "7.25-2=5.25 ANSWER FOR THE LENGTH OF THE UNKNOWN LEG. \n" ); document.write( "PROOF \n" ); document.write( "5.25^2+25=7.25^2 \n" ); document.write( "27.56+25=52.56 \n" ); document.write( "52.56=52.56 \n" ); document.write( " |