document.write( "Question 97667: One leg of a right triangle is 2 inches smaller than the hypotenuse. The other leg is 5 inches long. What are the lengths of the unknown leg and hypotenuse? \r
\n" ); document.write( "\n" ); document.write( "Not sure if I set it up right. \r
\n" ); document.write( "\n" ); document.write( "(x+2)^2 + 5^2 = x^2
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Algebra.Com's Answer #71076 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
LET X BE THE HYPOTENUSE.
\n" ); document.write( "ONE SIDE=(X-2)
\n" ); document.write( "THE OTHER SIDE=5
\n" ); document.write( "(X-2)^2+5^2=X^2
\n" ); document.write( "X^2-4X+4+25=X^2
\n" ); document.write( "-4X+29=0
\n" ); document.write( "-4X=-29
\n" ); document.write( "X=-29/-4
\n" ); document.write( "X=7.25 ANSWER FOR THE LENGTH OF THE HYPOTENUSE.
\n" ); document.write( "7.25-2=5.25 ANSWER FOR THE LENGTH OF THE UNKNOWN LEG.
\n" ); document.write( "PROOF
\n" ); document.write( "5.25^2+25=7.25^2
\n" ); document.write( "27.56+25=52.56
\n" ); document.write( "52.56=52.56
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