document.write( "Question 1096264: 1. A picture 6 dm more than its width is to be framed with 3 dm border. The total area of the border is 288 square dm. What are the dimensions of the pictures?
\n" ); document.write( "2. The area of a 12mx8m rectangle is to be doubled. By what equal amount must each dimensions be increased?
\n" ); document.write( "3. The product of two consecutive integers is 210. What are the numbers \n" ); document.write( "
Algebra.Com's Answer #710717 by jorel1380(3719)\"\" \"About 
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1.Let w and w+6 be the width and the length of the picture, respectively. Then, the frame would be w+6 by w+12. So:
\n" ); document.write( "(w+6)(w+12)-(w)(w+6)=288
\n" ); document.write( "Solve for w
\n" ); document.write( "2. Let n be the amount that both dimensions need to be increased. Then:
\n" ); document.write( "(12+w)(8+w)=2(12)(8)=192
\n" ); document.write( "w²+20w+96=192
\n" ); document.write( "w²+20w-96=0
\n" ); document.write( "Solve for w
\n" ); document.write( "3.Let n be the first integer. Then, the second would be n+1. So:
\n" ); document.write( "n(n+1)=210
\n" ); document.write( "n²+n-210=0
\n" ); document.write( "Solve for n
\n" ); document.write( "☺☺☺☺\r
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