document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1096276>Question 1096276</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cargo plane flew from the US across the Atlantic at 245 mph, and flew back to the US at 265 mph. Given that the first trip took two hours longer, how long was return trip?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #710714 by </B><A HREF=/tutors/aboutme.mpl?userid=sandeepvijay><B>sandeepvijay(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sandeepvijay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=710714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance = Speed * Time\r<BR>\n" );
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document.write( "Assuming that distance traveled in one way trip is D and time taken for the onward and return journey is T1 and T2, then\r<BR>\n" );
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document.write( "Since the distance traveled in both onward and return journey is same, we can say D = 245 * T1 = 265 * T2 ____________(1)\r<BR>\n" );
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document.write( "Also we know that the Time taken in first journey was 2 hours longer than the return journey, therefore\r<BR>\n" );
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document.write( "T1 - T2 = 2 or T1 = T2 + 2 ___________(2)\r<BR>\n" );
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document.write( "Substituting value T1 in equation (1), we will get \r<BR>\n" );
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document.write( "245* (T2+2) = 265 * T2 => 20*T2 = 490 => T2 = 24.5 hrs or 24 hrs and 30 mins<BR>\n" );
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