document.write( "Question 1096243: 7e^x=12-e^-x\r
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document.write( "Solve algebraically. The first (-) is subtraction and the last (-) is a negative x. Thanks in advance.
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Algebra.Com's Answer #710704 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 7e^x=12-e^-x \n" ); document.write( "------ \n" ); document.write( "multiply by e^x \n" ); document.write( "7e^(2x) = 12e^x - 1 \n" ); document.write( "7e^(2x) - 12e^x + 1 = 0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "============= \n" ); document.write( "e^x =~ 1.6264 \n" ); document.write( "x = ln(1.6264) \n" ); document.write( "------------------- \n" ); document.write( "e^x =~ 0.0878 \n" ); document.write( "x = ln(0.0878) \n" ); document.write( " \n" ); document.write( " |