document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=97678>Question 97678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bank loaned out php12.000, part of it at the rate of 8%per yaer and the rest at the rate of 18%per year. If the invest recieved totaled php1,000, how much was loaned at 8% </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71065 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71065\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A bank loaned out php12.000, part of it at the rate of 8%per yaer and the rest at the rate of 18%per year. If the invest recieved totaled php1,000, how much was loaned at 8%<BR>\n" );
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document.write( "Let amount invested at 8% be \"x\" ; interest on that is 0.08x dollars<BR>\n" );
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document.write( "Amt invested at 18^ is \"12,000-x\"; int is 0.18(1200-x)= 2160-0.18x dollars<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "interest + interest = 1000<BR>\n" );
document.write( "0.08x + 2160-0.18x = 1000<BR>\n" );
document.write( "-0.10x = -1160<BR>\n" );
document.write( "x = 11,600 (amount invested at 8%)<BR>\n" );
document.write( "12,000-11600 = 400 (amount invested at 18%)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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