document.write( "Question 1096175: Charles is one third as old as his father. In six years, Charles will be three sevenths as old as his father. If charles is less than 18 years old, how old is charles' father? \n" ); document.write( "
Algebra.Com's Answer #710639 by ankor@dixie-net.com(22740)\"\" \"About 
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Charles is one third as old as his father.
\n" ); document.write( "c = \"1%2F3\"f
\n" ); document.write( "or
\n" ); document.write( "f = 3c
\n" ); document.write( " In six years, Charles will be three sevenths as old as his father.
\n" ); document.write( "c + 6 = \"3%2F7\"(f + 6)
\n" ); document.write( "get rid of that annoying fraction, multiply both sides by 7
\n" ); document.write( "7(c + 6) = 3(f + 6)
\n" ); document.write( "7c + 42 = 3f + 18
\n" ); document.write( "7c = 3f + 18 - 42
\n" ); document.write( "7c = 3f - 24
\n" ); document.write( "Replace f with 3c
\n" ); document.write( "7c = 3(3c) - 24
\n" ); document.write( "7c = 9c - 24
\n" ); document.write( "24 = 9c - 7c
\n" ); document.write( "24 = 2c
\n" ); document.write( "c = 24/2
\n" ); document.write( "c = 12
\n" ); document.write( ":
\n" ); document.write( "If charles is less than 18 years old, how old is charles' father
\n" ); document.write( "f = 3(12)
\n" ); document.write( "f = 36 yrs is the age of the father
\n" ); document.write( ":
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\n" ); document.write( ":
\n" ); document.write( "Check this
\n" ); document.write( "12 + 6 = \"3%2F7\"(36+6)
\n" ); document.write( "18 = \"3%2F7\"*42
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