document.write( "Question 1096155: Frank had three-fourths of the problems right on a test. Lucilla had five-sixths of the
\n" ); document.write( "problems right, which was ten more problems right than Frank. \r
\n" ); document.write( "\n" ); document.write( "a) How many problems were on the test?
\n" ); document.write( "b) How many problems did Frank have right?
\n" ); document.write( "c) How many problems did Lucilla have right?\r
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Algebra.Com's Answer #710615 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
a)If Lucilla had 5/6ths of the answers right, and Frank had only 3/4ths, and the difference was 10, then:
\n" ); document.write( "5n/6 - 3n/4=10; where n is the total number of problems on the test. So:
\n" ); document.write( "10n/12 - 9n/12=10
\n" ); document.write( "n=120 questions on the test
\n" ); document.write( "b)3/4 x 120=90 problems right for Frank
\n" ); document.write( "c)5/6 x 120=100 problems right for Lucilla
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