document.write( "Question 1096076: Find the consecutive odd integers such that twice the product of the last two is 91 more than the product of the first \n" ); document.write( "
Algebra.Com's Answer #710545 by rothauserc(4718)\"\" \"About 
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let x, x+2, x+4 be three consecutive odd integers, then
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\n" ); document.write( "2 * [(x+2) * (x+4)] = x * (x+2) + 91
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\n" ); document.write( "2 * (x^2 +6x +8) = x^2 +2x +91
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\n" ); document.write( "2x^2 +12x +16 = x^2 +2x +91
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\n" ); document.write( "x^2 +10x -75 = 0
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\n" ); document.write( "(x+15) * (x-5) = 0
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\n" ); document.write( "x = -15 and x = 5
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\n" ); document.write( "there are two solutions
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\n" ); document.write( "1) 5, 7, 9
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\n" ); document.write( "2) -15, -17, -19
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