document.write( "Question 1096065: Find the equation of the circle which passes through points a(0,2), b(2,0) and c(-4,0) \n" ); document.write( "
Algebra.Com's Answer #710531 by ikleyn(52800)\"\" \"About 
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document.write( "1.  Considering the points A and B, you can conclude that the center lies in the straight line  y = x,  \r\n" );
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document.write( "    which is the angle bisector of the first and the third quadrants right angle.\r\n" );
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document.write( "2.  Considering the points B and C, you can conclude that the center lies in vertical line x = -1.\r\n" );
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document.write( "3.  From n1)  and  n2), it follows that the center is the point (x,y) = (-1,-1).\r\n" );
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document.write( "4.  The radius is  \"sqrt%28%28%28-1%29-0%29%5E2+%2B+%28%28-1%29-2%29%5E2%29\" = \"sqrt%281+%2B+9%29\" = \"sqrt%2810%29\".\r\n" );
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document.write( "5.  Thus the equation of the circle is \r\n" );
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document.write( "    \"%28x%2B1%29%5E2+%2B+%28y%2B1%29%5E2\" = 10.\r\n" );
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