document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1096031>Question 1096031</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is five inches more than four times its width. If the perimeter of the rectangle is 90 inches, find its dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #710520 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=710520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 4W+5<BR>\n" );
document.write( "2L + 2W = 90<BR>\n" );
document.write( "2(4W+5) + 2W = 90<BR>\n" );
document.write( "8W + 10 + 2W = 90<BR>\n" );
document.write( "10W + 10 = 90<BR>\n" );
document.write( "10W = 80<BR>\n" );
document.write( "W = 8 this is the width.<BR>\n" );
document.write( "L = 4W+5 = 4(8)+5 = 37<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "2L + 2W = 90<BR>\n" );
document.write( "2(37) + 2(8) = 90<BR>\n" );
document.write( "74 + 16 = 90 Correct<BR>\n" );
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