document.write( "Question 97639: Dear Tutor/or Tutors,
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document.write( "I would greatly appreciate it if you can help me solve the following problem and let me know how you did so;\r
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document.write( "5 more than two thirds of the number is the same as 3 less than one half of the number.\r
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document.write( "Thank You Very Much! \n" );
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Algebra.Com's Answer #71042 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! The number you are looking for is unknown. So call it x. \n" ); document.write( ". \n" ); document.write( "Two-thirds of the number is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and 5 more than that is written as: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "That is the same (meaning equal to) 3 less than one-half the number. One-half the number is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and 3 less than that is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "So now we have two sides that are to be equal. In equation form this is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Let's get rid of the fractions by multiplying both sides of this equation (all terms) by \n" ); document.write( "a common denominator of 6. (Note that we get 6 by multiplying the two denominators of \n" ); document.write( "3 and 2). Multiplying both sides of the equation (all terms) by 6 results in the equation \n" ); document.write( "becoming: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Doing the division in the two sets of parentheses simplifies the equation to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Get rid of the 3x on the right side by subtracting 3x from both sides. When you do that \n" ); document.write( "the equation reduces to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now get rid of +30 on the left side by subtracting 30 from both sides to end up with: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "That's the answer. Let's check it by using it in the original problem statement. \n" ); document.write( ". \n" ); document.write( "One-third of -48 is -16. So two-thirds of -48 is -32. 5 more than -32 is - 27 (-32 + 5 = -27). \n" ); document.write( ". \n" ); document.write( "That is to be equal to 3 less than one-half the number. One-half of -48 is - 24 and if you take \n" ); document.write( "away 3 from -24 you have (-24 - 3) -27. So the answer of -27 works because it makes both \n" ); document.write( "sides of the equation equal to -27. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand this problem. Getting rid of the fractions is a technique \n" ); document.write( "that often saves you from the complexity of multiplying, dividing, adding, and subtracting \n" ); document.write( "in fractional form. Hope that helps. \n" ); document.write( ". \n" ); document.write( " |