document.write( "Question 1095903: determine whether the equation defines y as a function of x\r
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\n" ); document.write( "\n" ); document.write( "X2+6y=4
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Algebra.Com's Answer #710411 by Theo(13342)\"\" \"About 
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start with x^2 + 6y = 4\r
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\n" ); document.write( "\n" ); document.write( "subtract x^2 from both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "6y = 4 - x^2\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of this eqaution by 6 to get:\r
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\n" ); document.write( "\n" ); document.write( "y = (4 - x^2) / 6\r
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\n" ); document.write( "\n" ); document.write( "offhand i would say yes because there is only one value of y for each and every value of x.\r
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\n" ); document.write( "\n" ); document.write( "for example, assume that x = 2.\r
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\n" ); document.write( "\n" ); document.write( "y = (4-4) / 6 which is equal to 0.\r
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\n" ); document.write( "\n" ); document.write( "assume that x = -2.\r
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\n" ); document.write( "\n" ); document.write( "y = (4-4) / 6 which is equal to 0.\r
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\n" ); document.write( "\n" ); document.write( "you have the same value of y for two different values of x, but you don't have the same value of x for two different values of y, therefore y is a function of x.\r
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\n" ); document.write( "\n" ); document.write( "the graph will show this to be true.\r
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\n" ); document.write( "\n" ); document.write( "that graph is shown below:\r
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\n" ); document.write( "\n" ); document.write( "give the graph the vertical line test and you will see that there is only one value of y for each and every value of x.\r
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