document.write( "Question 1095871: Please help simplify the following:
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document.write( "((6x^2)/ (x^2+2x+4))/ ((x^3-8) /(-6x+12))\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #710367 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! ((6x^2)/ (x^2+2x+4))/ ((x^3-8) /(-6x+12)) \n" ); document.write( "The numerator becomes 6x^2/(x^2+2x+4) \n" ); document.write( "The denominator becomes -(x-2)(x^2+2x+4)/(6x-12), because if I put a negative sign out front, one of the two terms may be negated without changing the fraction. \n" ); document.write( "This becomes -(x-2)/(x^2+2x+4)/6(x-2). That becomes -(1/6(x^2+2x+4) \n" ); document.write( "The trinomials cancel since they are both denominators. \n" ); document.write( "This becomes 6x^2/-(1/6)=-36x^2\r \n" ); document.write( "\n" ); document.write( "Let x=3 \n" ); document.write( "the original is 54/19 divided by 19/-6 \n" ); document.write( "That is -324 \n" ); document.write( "-36x^2=-324 \n" ); document.write( " |