document.write( "Question 1095822: Joey and Mark go on vacation and travel in opposite directions. Joey leaves the house at 8 AM and averages 35 mph. Mark leaves at 9 AM and averages 40 mph. A what time will they be 225 miles apart? \n" ); document.write( "
Algebra.Com's Answer #710345 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 40m+35*(m+1)=225 \n" ); document.write( "40m+35m+35=225 \n" ); document.write( "75m=190 \n" ); document.write( "m=190/75 \n" ); document.write( "m=2.53333333333 \n" ); document.write( "m=2 hours 32 minutes \n" ); document.write( "They will be 225 miles apart at 12:32 pm \n" ); document.write( "check \n" ); document.write( "2.53333333333*40+3.53333333333*35=225 \n" ); document.write( "ok\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |