document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1095828>Question 1095828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 7 foot long piece of pipe has an outside diameter of 3.50 inches. and the volume of in the pipe is equal to 449 inches cubed(449in^3). find the wall thickness? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #710319 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=710319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> OD Ø = 3.5<BR>\n" );
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document.write( "7 x 12 = 84 inches long<BR>\n" );
document.write( "449/84 = 5.35 <BR>\n" );
document.write( "ID (Internal Diameter): 2 x (5.35/Pi) = 3.4<BR>\n" );
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document.write( "3.5 - 3.4 = 0.1; 0.1/2 = 0.05 inches is the wall thickness of the tube.<BR>\n" );
document.write( "NOTE: This is a very thin tube, 0.05 is about the thickness of printing paper </SPAN>\n" );
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