document.write( "Question 1095811: The sum of the years of the mother and the daughter is 56. 5 years ago the mother was 2 times older than the daughter. How old are they now?
\n" ); document.write( "The solving looks something like
\n" ); document.write( "x+y=56
\n" ); document.write( "(x-5)=(y-5)*2
\n" ); document.write( "Please explain thoroughly and step by step :)
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #710300 by Alan3354(69443)\"\" \"About 
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The sum of the years of the mother and the daughter is 56. 5 years ago the mother was 2 times older than the daughter. How old are they now?
\n" ); document.write( "The solving looks something like
\n" ); document.write( "x+y=56
\n" ); document.write( "(x-5)=(y-5)*2
\n" ); document.write( "---------------
\n" ); document.write( "1 time older = 100% older = 2x as old
\n" ); document.write( "2 times older = 200% older = 3x as old
\n" ); document.write( "==========
\n" ); document.write( "I would use m & d instead of x & y
\n" ); document.write( "----
\n" ); document.write( "m + d = 56
\n" ); document.write( "m-5 = 3*(d-5) = 3d - 15 --> m - 3d = -10
\n" ); document.write( "---
\n" ); document.write( "m - 3d = -10
\n" ); document.write( "m + d = 56
\n" ); document.write( "--------------------- Subtract
\n" ); document.write( "-4d = -66
\n" ); document.write( "d = 16.5
\n" ); document.write( "m = 39.5\r
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