document.write( "Question 1095742: A solution of salt and water is 20% salt. If 25% of the water is removed, what is the percentage of salt in the new solution? \n" ); document.write( "
Algebra.Com's Answer #710256 by josmiceli(19441)\"\" \"About 
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I can pick any quantity of water
\n" ); document.write( "since no quantity is given:
\n" ); document.write( "Let \"+500+\" = the quantity of salt and water in the solution ( any units )
\n" ); document.write( "\"+.2%2A500+=+100+\" = the quantity of salt in the solution
\n" ); document.write( "\"+400+\" = the quantity of water in solution
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\n" ); document.write( "\"+400+-+.25%2A400+=+.75%2A400+\"
\n" ); document.write( "\"+.75%2A400+=+300+\"
\n" ); document.write( "remaining water + salt is:
\n" ); document.write( "\"+300+%2B+100+=+400+\"
\n" ); document.write( "----------------------
\n" ); document.write( "\"+%28+100+%2F+400+%29%2A100+=+25+\"
\n" ); document.write( "The % of salt in new solution is 25%\r
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