document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1095687>Question 1095687</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two hoses, when connected to a swimming pool,can fill the pool together in 4 hours. If the larger hose alone is used, it can fill the pool in 6 hours less than the smaller hose. How long will it take the smaller hose to fill the swimming pool alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #710242 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=710242\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Two hoses, when connected to a swimming pool, can fill the pool together in 4 hours.<BR>\n" );
document.write( " If the larger hose alone is used, it can fill the pool in 6 hours less than the smaller hose.<BR>\n" );
document.write( " How long will it take the smaller hose to fill the swimming pool alone?<BR>\n" );
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document.write( "Let s = time required by the small hose to fill the pool alone<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(s-6) = time required by the large hose<BR>\n" );
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document.write( "Let the completed job = 1 (a full pool)<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Each hose does a fraction of the job, the two fractions add up to 1<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F%28%28s-6%29%29 ALIGN=MIDDLE  ALT=\"4%2F%28%28s-6%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2Fs ALIGN=MIDDLE  ALT=\"4%2Fs\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1<BR>\n" );
document.write( "multiply equation by s(s-6)<BR>\n" );
document.write( "s(s-6)*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F%28%28s-6%29%29 ALIGN=MIDDLE  ALT=\"4%2F%28%28s-6%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = s(s-6)*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2Fs ALIGN=MIDDLE  ALT=\"4%2Fs\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1s(s-6)<BR>\n" );
document.write( "Cancel the denominators and you have<BR>\n" );
document.write( "4s + 4(s-6) = s^2 - 6s<BR>\n" );
document.write( "4s + 4s - 24 = s^2 - 6s<BR>\n" );
document.write( "8s - 24= s^2 - 6s<BR>\n" );
document.write( "arrange as a quadratic equation<BR>\n" );
document.write( "0 = s^2 - 6s - 8s + 24<BR>\n" );
document.write( "s^2 - 14s + 24 = 0<BR>\n" );
document.write( "Factors to<BR>\n" );
document.write( "(s-12)(s-2) = 0<BR>\n" );
document.write( "two solutions<BR>\n" );
document.write( "s = 2 <BR>\n" );
document.write( "and the reasonable solution<BR>\n" );
document.write( "s = 12 hrs is time required to fill the pool with the small hose<BR>\n" );
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document.write( "the large hose takes 6 hrs less, therefore<BR>\n" );
document.write( "6 hrs is the time required by the large hose<BR>\n" );
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document.write( ":<BR>\n" );
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document.write( "See if that checks out<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F6 ALIGN=MIDDLE  ALT=\"4%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F12 ALIGN=MIDDLE  ALT=\"4%2F12\"   DISABLED_style= \"max-width:90%; height:auto;\" > =<BR>\n" );
document.write( "reduce fractions<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1 <BR>\n" );
document.write( " </SPAN>\n" );
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