document.write( "Question 1095712: Please help...
\n" ); document.write( "A committee of four is selected from seven men and six women. Find the probability that there is at least one of each gender on the committee.
\n" ); document.write( "The answer should be 133/143, but I got it wrong.
\n" ); document.write( "Thank you.
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Algebra.Com's Answer #710235 by KMST(5347)\"\" \"About 
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With 7+6=13 people, you can form \"13%2A12%2A11%2A10%2F%282%2A3%2A4%29\" committees of 4 people.
\n" ); document.write( "Among those there are the only \"7%2A6%2A5%2A4%2F%282%2A3%2A4%29\" made of all men,
\n" ); document.write( "and the only \"6%2A5%2A4%2A3%2F%282%2A3%2A4%29\" made of all women.
\n" ); document.write( "The other committees have at least one person of each gender.
\n" ); document.write( "Those are
\n" ); document.write( "\"%2813%2A12%2A11%2A10-7%2A6%2A5%2A4-6%2A5%2A4%2A3%29%2F%282%2A3%2A4%29\"=\"%2813%2A4%2A3%2A11%2A5%2A2-%286%2A5%2A4%29%287%2B3%29%29%2F%282%2A3%2A4%29\"=\"%2813%2A11%2A6%2A5%2A4-6%2A5%2A4%2A11%29%2F%282%2A3%2A4%29\"=
\n" ); document.write( "of the total ={{143*6*5*4/(2*3*4}}} .
\n" ); document.write( "The probability is the ratio of those two quantities,
\n" ); document.write( "\"133%2A6%2A5%2A4%2F%28143%2A6%2A5%2A4%29=highlight%28133%2F143%29\" .
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\n" ); document.write( "If you got \"139%2F143\" the mistake was that
\n" ); document.write( "\"13%2A12%2A11%2A10-7%2A6%2A5%2A4-3%2A6%2A5%2A4\"
\n" ); document.write( "is equal to
\n" ); document.write( "and not to \"13%2A12%2A11%2A10-%287-3%29%2A6%2A5%2A4\" .
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