document.write( "Question 1095657: Jose can drive his car 50 mph and cover a certain distance in 20 minutes less than when he drives at 45 mph. Find that distance. \n" ); document.write( "
Algebra.Com's Answer #710163 by ikleyn(52803)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "Literal translation of the condition to a Math equation is this:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Let D be the distance under the question. Then\r\n" );
document.write( "\r\n" );
document.write( "    \"D%2F45+-+D%2F50\" = \"1%2F3\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Here D/45 is the time spent at the rate 45 mph;\r\n" );
document.write( "\r\n" );
document.write( "     D/50 is the time spent at the rate 50 mph;\r\n" );
document.write( "\r\n" );
document.write( "and \"1%2F3\" = \"1%2F3\" of an hour = 20 minutes is the time difference, given by the condition.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "To solve, multiply both sides by 450 to get\r\n" );
document.write( "\r\n" );
document.write( "10*D - 9*D = 150,\r\n" );
document.write( "\r\n" );
document.write( "which implies  D = 150 kilometers.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );