document.write( "Question 1095657: Jose can drive his car 50 mph and cover a certain distance in 20 minutes less than when he drives at 45 mph. Find that distance. \n" ); document.write( "

Algebra.Com's Answer #710162 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Jose can drive his car 50 mph and cover a certain distance in 20 minutes less than when he drives at 45 mph.
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\n" ); document.write( "change 20 min to 1/3 hr
\n" ); document.write( "let t = time required at 45 mph
\n" ); document.write( "then
\n" ); document.write( " $\"%28t-1%2F3%29\"$ = time at 50 mph
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( "45t = 50(t - 1/3))
\n" ); document.write( "45t = 50t - $\"50%2F3\"$
\n" ); document.write( "45t - 50t = $\"-50%2F3\"$
\n" ); document.write( "-5t = $\"-50%2F3\"$
\n" ); document.write( "multiply both sides by -3
\n" ); document.write( "15t = 50
\n" ); document.write( "t = 50/15
\n" ); document.write( "t = 3 $\"1%2F3\"$ hrs at 45 mph
\n" ); document.write( "then
\n" ); document.write( "3 hrs = time required at 50 mph
\n" ); document.write( "\"Find that distance \"
\n" ); document.write( "50 * 3 = 150 mi
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check the distance at 45 mph
\n" ); document.write( "45 * 3.333 = 150 mi also \n" ); document.write( "

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