document.write( "Question 97604: Science and medicine. The equation h=-16t^2+112t gives the height of an
\n" ); document.write( "arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180 ft.Solve to the nearest thousandth.
\n" ); document.write( " Please help me. I need to show all of the work and I am stumped. I have a horrible problem with word problems.\r
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Algebra.Com's Answer #71014 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The equation h=-16t^2+112t gives the height of an arrow, shot upward from the ground
\n" ); document.write( "with an initial velocity of 112 ft/s,
\n" ); document.write( "where t is the time after the arrow leaves the ground.
\n" ); document.write( "Find the time it takes for the arrow to reach a height of 180 ft.Solve to the nearest thousandth.
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\n" ); document.write( "h(t) = -16t^2+112t
\n" ); document.write( "Let h(t)= 180 ft and solve for \"t\":\r
\n" ); document.write( "\n" ); document.write( "-16t^2+112t=180
\n" ); document.write( "-16t^2+112t-180 = 0
\n" ); document.write( "Divide thru by -4 to get:
\n" ); document.write( "4t^2 -28t + 45 = 0
\n" ); document.write( "Use the quadratic formula to get:\r
\n" ); document.write( "\n" ); document.write( "t = [28 +- sqrt(28^2 - 4*4*45)]/8\r
\n" ); document.write( "\n" ); document.write( "t = [28 +- sqrt64)]/8\r
\n" ); document.write( "\n" ); document.write( "t = [28 +- 8]/8\r
\n" ); document.write( "\n" ); document.write( "t = (28+8)/8 = 4.5 seconds (time when the arrow is on the way down)
\n" ); document.write( "t = (28-8)/8 = 2.5 seconds (time when the arrow is on the way up)\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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