document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1095575>Question 1095575</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangular field is 1000 yd2.Two parallel sides are fenced with aluminum at $15/yd. One of the remaining sides is fenced with steel at $10/yd, and all but 10 yd of the remaining side is fenced with wood costing $5/yd.The remaining 10 yd are left unfenced.The total cost of the fencing is $1525. a. What is the length of the side fenced with steel? b. What is the length of each side fenced with aluminum?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #710109 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=710109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangular field is 1000 yd2.<BR>\n" );
document.write( " Two parallel sides are fenced with aluminum at $15/yd.<BR>\n" );
document.write( " One of the remaining sides is fenced with steel at $10/yd, and<BR>\n" );
document.write( " all but 10 yd of the remaining side is fenced with wood costing $5/yd.<BR>\n" );
document.write( " The remaining 10 yd are left unfenced.<BR>\n" );
document.write( " The total cost of the fencing is $1525. <BR>\n" );
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document.write( "a. What is the length of the side fenced with steel?<BR>\n" );
document.write( "let L = the length fenced with aluminum<BR>\n" );
document.write( "let w = the fence with steel<BR>\n" );
document.write( "then<BR>\n" );
document.write( "L* w = 1000 sq/yds<BR>\n" );
document.write( "and<BR>\n" );
document.write( "15(2L) + 10w + 5(w-10) = 1525<BR>\n" );
document.write( "30L + 10w + 5w - 50 = 1525<BR>\n" );
document.write( "30L + 15w = 1525 + 50<BR>\n" );
document.write( "30L + 15w = 1575<BR>\n" );
document.write( "simplify, divide eq by 15<BR>\n" );
document.write( "2L + w = 105<BR>\n" );
document.write( "w = 105 - 2L<BR>\n" );
document.write( "Using the area equation, replace w with (105-2L)<BR>\n" );
document.write( "L(105-2L) = 1000<BR>\n" );
document.write( "A quadratic equation<BR>\n" );
document.write( "-2L^2 + 105L - 1000 = 0<BR>\n" );
document.write( "we can use the quadratic formula; a=-2;b=105, c=-1000; but this will factor<BR>\n" );
document.write( "(2L - 25)(L - 40) = 0<BR>\n" );
document.write( "two solutions<BR>\n" );
document.write( "2L = 25<BR>\n" );
document.write( "L = 12.5 yds<BR>\n" );
document.write( "and<BR>\n" );
document.write( "L = 40 yds, this is the reasonable solution for length using aluminum<BR>\n" );
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document.write( "then<BR>\n" );
document.write( "w = 105 - 2(40)<BR>\n" );
document.write( "w = 25 yds is fenced with steel<BR>\n" );
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document.write( "Check this by finding the total cost with these values for L and w<BR>\n" );
document.write( "15(2*40) + 10(25) + 5(25-10) =<BR>\n" );
document.write( "1200 + 250 + 75 = 1525 </SPAN>\n" );
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