document.write( "Question 1095567: Hi, could you please help me with this question:\r
\n" ); document.write( "\n" ); document.write( "3e^x = 5 + 8e^-x\r
\n" ); document.write( "\n" ); document.write( "- How do you solve for x when the power is negative?
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Algebra.Com's Answer #710074 by ikleyn(52800)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "1.  First step: introduce new variable u = \"e%5Ex\".\r\n" );
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document.write( "    Then your equation takes the form\r\n" );
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document.write( "    3u = 5 + \"8%2Fu\".    (1)\r\n" );
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document.write( "2.  Second step:  multiply by \"u\" both sides:\r\n" );
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document.write( "     3u^2 = 5u + 8,   or\r\n" );
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document.write( "     3u^2 - 5u - 8 = 0.\r\n" );
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document.write( "3.  You got quadratic equation. Its roots are\r\n" );
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document.write( "    \"u%5B1%2C2%5D\" = \"%285+%2B-+sqrt%285%5E2+%2B+4%2A3%2A8%29%29%2F%282%2A3%29\" = \"%285+%2B-+11%29%2F6\".\r\n" );
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document.write( "    a)  \"u%5B1%5D\" = \"%285+%2B+11%29%2F6\" = \"16%2F6\" = \"8%2F3\";\r\n" );
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document.write( "        ========>  \"e%5Ex\" = \"8%2F3\"  ====>  x = \"ln%288%2F3%29\".\r\n" );
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document.write( "    b)  \"u%5B2%5D\" = \"%285-11%29%2F6\"  = -1.\r\n" );
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document.write( "        ========>   \"e%5Ex\" = -1   ====> There is NO solution for x.\r\n" );
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document.write( "Answer.  The given equation has a unique solution  x = \"ln%288%2F3%29\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "Introducing new variable is the standard method of solving such equations.\r
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