document.write( "Question 1095569: #1) log4(x) + log4(x-3) = 1
\n" ); document.write( "This is what I've tried:
\n" ); document.write( "x(x-3) = 1
\n" ); document.write( "x^2 - 3x -1 = 0 ----> I can't factorise so do I need to complete the square to find x or is there an easier way of doing it?\r
\n" ); document.write( "\n" ); document.write( "#2) log10(2x^2+3x+3) - log10(1-2x) = 1
\n" ); document.write( "I'm having the same factorising issue here.\r
\n" ); document.write( "\n" ); document.write( "Thankyou so much
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Algebra.Com's Answer #710073 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Is the base of log, 4 ?\r
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\n" ); document.write( "\n" ); document.write( "\"log%284%2Cx%29%2Blog%284%2C%28x-3%29%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%284%2C%28x%28x-3%29%29%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"4%5E1=x%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-3x-4=0\", and you can take the rest from here.
\n" ); document.write( "You want the logarithms of non-negative numbers.
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