document.write( "Question 1095549: A chemist has a 1% solution of alcohol to mix with a 56% solution to get 110L of a final mixture that is 26% alcohol. How much of each of the original solutions should he use? \n" ); document.write( "
Algebra.Com's Answer #710051 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"x%2B56%28110-x%29=26%2A110\", x for how much of the 1% alcohol\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B56%2A110-56x=26%2A110\"\r
\n" ); document.write( "\n" ); document.write( "\"-55x=26%2A110-56%2A110\"\r
\n" ); document.write( "\n" ); document.write( "\"55x=%2856-26%29%2A110\"\r
\n" ); document.write( "\n" ); document.write( "\"x=2%2856-26%29\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=60%29\"----------Liters of the 1% alcohol.
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\n" ); document.write( "\"highlight%2850%29\"-----------Liters of the 56% alcohol
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