document.write( "Question 1095529: Justin has $4.75 in quarters, dimes, and nickels. If he has a total of 27 coins and he has twice as many dimes as nickels, how many of each coin does he have? \n" ); document.write( "
Algebra.Com's Answer #710041 by Edwin McCravy(20060)\"\" \"About 
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he has twice as many dimes as nickels,
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document.write( "Let N = number of nickels\r\n" );
document.write( "Then 2N = the number of dimes.\r\n" );
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\n" ); document.write( "he has a total of 27 coins
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document.write( "Number of quarters =  27 -    N    -    2N \r\n" );
document.write( "Number of quarters =  27 - 3N \r\n" );
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\n" ); document.write( "Justin has $4.75 in quarters, dimes, and nickels
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document.write( "   0.25N   +  0.10(2N) + 0.05(27-3N) =  4.75\r\n" );
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document.write( "Move the decimals two places right in each term:\r\n" );
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document.write( "     25N   +    10(2N) +    5(27-3N) =   475\r\n" );
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document.write( "Simplify and solve that for N, the number of nickels, \r\n" );
document.write( "then substitute what you get for N in:\r\n" );
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document.write( "2N = the number of dimes\r\n" );
document.write( "27 - 3N = the number of quarters\r\n" );
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document.write( "Edwin
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