document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=206>Question 206</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A person invested $2,000, part at 7% and part at 8% simple interest. If the total yearly interest from these investments was $154, how much was vested at each rate?\r<BR>\n" );
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document.write( "How many gallons of a 70% alcohol solution must be mixed with 30 gallons of a 15% alcohol solution to obtain a solution that is 60% alcohol? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71 by </B><A HREF=/tutors/aboutme.mpl?userid=ichudov><B>ichudov(507)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ichudov><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ichudov><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You should ask two questions separately, but here goes. <BR>\r<BR>\n" );
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document.write( "Denote the amount invested at 7% as x dollars. The remaining amount to be invested is, obviously, 2000-x. Amount of interest at 7% is x*0.07. Amount of interest invested at 8% is (2000-x)*0.08. So, we have x*0.07+(2000-x)*0.08 = 154. <BR>\r<BR>\n" );
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document.write( "x*0.07+2000*0.08 - x*0.08 = 154<BR><BR>\n" );
document.write( "2000*0.08-154 + x*0.07 - x*0.08 = 0<BR><BR>\n" );
document.write( "160-154-0.01x = 0<BR><BR>\n" );
document.write( "6 = 0.01x<BR><BR>\n" );
document.write( "x = 600, 2000-x = 1400<BR><BR>\n" );
document.write( "Answer: He invested $600 at 7% and $1,400 at 8%.<BR>\r<BR>\n" );
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document.write( "Regarding your unhealthy interest in alcohol solutions :), I have a word problem solver for exactly this problem. Go to word problems from my <A  rel=nofollow HREF=/>home page</A>. </SPAN>\n" );
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