document.write( "Question 1095341: Events A and B are mutually exclusive. Suppose P(A)=0.21 and P(B)=0.05.
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Algebra.Com's Answer #709994 by Edwin McCravy(20064)\"\" \"About 
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document.write( "The probability that neither occur is the complement of the\r\n" );
document.write( "event that A or B occurs. \r\n" );
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document.write( "So we will first calculate P(A or B)\r\n" );
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document.write( "P(A or B) = P(A) + P(B) - P(A and B)\r\n" );
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document.write( "But since they are mutually exclusive, P(A and B) = 0\r\n" );
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document.write( "P(A or B) = P(A) + P(B) - P(A and B)\r\n" );
document.write( "P(A or B) = P(A) + P(B) - 0\r\n" );
document.write( "P(A or B) = P(A) + P(B)\r\n" );
document.write( "P(A or B) = 0.21 + 0.05\r\n" );
document.write( "P(A or B) = 0.26\r\n" );
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document.write( "The complement of the event (A or B) has probability\r\n" );
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document.write( "1 - 0.26 = 0.74\r\n" );
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document.write( "Edwin
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