document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1095461>Question 1095461</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This year, serena is one-seventh of her cousin's age.  Two years from now, serena will be one-fourth of her cousein's age.  In how many years will serena be half her cousin's age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #709980 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=709980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This year, serena is one-seventh of her cousin's age.  Two years from now, serena will be one-fourth of her cousein's age.  In how many years will serena be half her cousin's age? <BR>\n" );
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document.write( "S = C/7<BR>\n" );
document.write( "S+2 = (C+2)/4<BR>\n" );
document.write( "Find their ages.<BR>\n" );
document.write( "Sub for S in the 2nd eqn:<BR>\n" );
document.write( "C/7 + 2 = (C+2)/4<BR>\n" );
document.write( "4C + 56 = 7(C+2) = 7C+14<BR>\n" );
document.write( "C = 14<BR>\n" );
document.write( "S = 2<BR>\n" );
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document.write( "Difference = 12 years.<BR>\n" );
document.write( "--> 1/2 at ages 12 & 24<BR>\n" );
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document.write( "In how many years will serena be half her cousin's age? <BR>\n" );
document.write( "In 10 years. </SPAN>\n" );
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